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BIRADS classification

BIRADS classification is applied for each breast independent or sum of both breasts?

e.g: RT Breast BIRADS I
       LT Breast BIRADS IV

or    Together will be BIRADS IV
5 Responses
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25201 tn?1255580836
RT breast BIRADS 4 -- LT breast BIRADS 2 Abnormalities in both breasts are NEVER combined. If you combined them it would indicate that both required a biopsy and in this case only the R breast requires the biopsy. The BIRADS scoring system indicates what type of further investigation is required of each suspicious finding.
Helpful - 1
Avatar universal
Thank you for reply.
I will ask my question in different way.
I am reporting a mammography films 4views CC and MLO
In one side there was a positive lesion say BIRADS 4
In the other side there was a benign findiing BIRADS 2
In the final conclusion of the report?
Do I describ each breast separetly i.e:
RT Breast BIRADS 4
LT Breast BIRADS 2

or I will conclude my report using single BIRADS for both breasts i.e BIRADS 4 in this situation?
Helpful - 0
Avatar universal
Thank you for reply.
I will ask my question in different way.
I am reporting a mammography films 4views CC and MLO
In one side there was a positive lesion say BIRADS 4
In the other side there was a benign findiing BIRADS 2
In the final conclusion of the report?
Do I describ each breast separetly i.e:
RT Breast BIRADS 5
LT Breast BIRADS 2

or I will conclude my report using single BIRADS for both breasts i.e BIRADS 4 in this situation?
Helpful - 0
242527 tn?1292449140
MEDICAL PROFESSIONAL
Dear ismailghoneim:  BIRADs is based on the interpretation of an abnormality.  A BIRAD 4 would indicate the need for additional evaualuation of the abnormality in the left breast.  A BIRAD 1 is a normal finding.  There is nothing that needs evaluation in the right breast.
Helpful - 0
25201 tn?1255580836
BIRADS scoring is done regarding each susupicious area or abnormality that is found .... not on the breast as a whole. BIRADS 1 is benign finding. BIRADS 4 requires a biopsy to determine the nature of the abnormality found.
Helpful - 0

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