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How do I read this HCV RNA Viral Load lab work?

The lab work was positive for antibodies so further lab work was done.
HCV RNA QUANT PCR (CQ)
Value: 10.2E6 Iu/ml
Value: 7.01 log iu/ml

Real-time polymerase chain reaction. Reportable range is 15 IU / ml to 100,000,000 IU / ml (1.18 log iu/ml to 8.0 log iu/ml)

Having a hard time understanding what the top number is when it seems the top number isn't even in within measurable range yet the bottom number seems pretty high according to the log iu/ml listed beneath.
Or is the top number some antibody protein with the E6 on it?

Waiting on first appointment but would like to know where it stands before I walk in.
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683231 tn?1467323017
The value 10.2E6 is written in scientific notation or as an exponential entry. It is a short way to write a very large number. It is read as 10.2 times 10 to the 6th power or more commonly 10.2 x 10 ^6.

Basically 10.2 times 10 multiplied by itself 6 times.

The final result would be 10,200,000 or as willbb has already said 10.2 million.
Helpful - 0
Avatar universal
You have tested positive for Hepatitis C with a viral load of 10.2 million. The log number is just another way to state that.
HCV is relatively easy to cure now so hopefully you have a follow up with your physician to do some further tests( genotyping , current amount of liver fibrosis) and discuss a treatment plan
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